Example To Display Image Using Servlet

In this instance, we are making use of FileInputStream class to study images and the ServletOutputStream class for writing this image content as a reply. In this we used the BufferedInputStream and BufferedOutputStream class, to make the performance faster.

You require to make use of the content type image/jpeg.

We are presuming that you already have a java.jpg image inside the c:\test directory, in this example. You can switch the location correspondingly.

To produce this application, three files are created:

1. index.html
2. DisplayImage.java
3. web.xml

Index.html

This file makes a link that supplicates the servlet. Servlet1 is the Url pattern of the Servlet.

<a href="servlet1">click for photo</a>

DisplayImage.java

This servlet class studies the image from the given directory and writes down the content in the replying object by making use of ServletOutputStream and BufferedOutputStream classes.

package com.javatpoint;  
import java.io.*;  
import javax.servlet.*;  
import javax.servlet.http.*;  
public class DisplayImage extends HttpServlet {  
  
    public void doGet(HttpServletRequest request,HttpServletResponse response)  
             throws IOException  
    {  
    response.setContentType("image/jpeg");  
    ServletOutputStream out;  
    out = response.getOutputStream();  
    FileInputStream fin = new FileInputStream("c:\\test\\java.jpg");  
      
    BufferedInputStream bin = new BufferedInputStream(fin);  
    BufferedOutputStream bout = new BufferedOutputStream(out);  
    int ch =0; ;  
    while((ch=bin.read())!=-1)  
    {  
    bout.write(ch);  
    }  
      
    bin.close();  
    fin.close();  
    bout.close();  
    out.close();  
    }  
}  

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